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5x^2+67x+30=0
a = 5; b = 67; c = +30;
Δ = b2-4ac
Δ = 672-4·5·30
Δ = 3889
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(67)-\sqrt{3889}}{2*5}=\frac{-67-\sqrt{3889}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(67)+\sqrt{3889}}{2*5}=\frac{-67+\sqrt{3889}}{10} $
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